CR9 posted :
can anyone help me with my son's homework? I could do the 3rd and 4th ones but left smoked for the rest:(
thanks in advance everyone!
(i) is just finding common factor.
(ii) is ambiguous... how can you cancel the 6 just like that? This is not division, or any other recognized mathematical method.
(iii) the question already doesnâ€™t make sense. If follow the equation stated in the question, the second number is 3, not 2.
Forget about the (iv).
What kind of question is this?
Is this a joke?
Donâ€™t insult our intelligence leh.
(i) If we rearrange, we get
(10p + d) / (10d + q) = p/q
Comparing, we get
p = 1, q = 4 and d = 6
(ii) Expanding the first equation, we get
10pq + dq = 10 pd + pq
9pq + dq - 10pd = 0
I am unsure of the syllabus, of the level, at which this question is pitched at.
So, I would do a trial and error method to solve, which may or may not be in syllabus given the lack of information
p = 1 gives us an answer already
The other 3 cases (apart from p, q, and d the same numbers, and non-zeros)
p = 1, q = 5 and d = 9
p = 2, q = 5 and d = 6
p = 4, q = 8 and d = 9
Sorry, am unsure which other questions you are not sure about. Please do indicate.